2070 magh (Q). The reflection takes place at a height of 350km and the maximum density in the ionosphere corresponds to a 0.75 refractive index at 10MHz. What will be the range (assume the earth is flat) for which MUF is 12MHz.
by 0 μ = √(1-81N/f2 ) 0.75 = √(1-81N/(10*106 ) Nmax =5.4*1011 fc = 9√(Nmax ) =6.614*106 Hz and Dskip = 2h √((fmuf /fc)2 -1) =2*350√((12*106 /(6.614*106 …