8.9 dB = 10log(Pt /Pr )
Pt /Pr = 7.76
Pr/ Pt = 1/7.76 = 0.1288
Given, r = 0.45 m
λ = 3*10^8/(10*10^9) = 0.03
and
D = 4πr* √(Pr/ Pt )/ λ
= 4π *0.45 √ 0.1288/0.03
D = 67.64
D (dB) = 10 log(67.64)
D (dB) =18.3 dB
(Q). While measuring the gain of a horn antenna the gain oscillator was set for 10GHz frequency and attenuation inserted was found to be 8.9dB. Calculate the gain of horn, the distance between two horns was 45 cm.
by 